Standard C++ Library Copyright 1998, Rogue Wave Software, Inc. NAME remove_if - Moves desired elements to the front of a container, and returns an iterator that describes where the sequence of desired elements ends. SYNOPSIS #include <algorithm> template <class ForwardIterator, class Predicate> ForwardIterator remove_if (ForwardIterator first, ForwardIterator last, Predicate pred); DESCRIPTION The remove_if algorithm eliminates all the elements referred to by iterator i in the range [first, last) for which the following corresponding condition holds: pred(*i) == true. remove_if returns an iterator that points to the end of the resulting range. remove_if is stable, which means that the relative order of the elements that are not removed is the same as their relative order in the original range. remove_if does not actually reduce the size of the sequence. It actually: 1) copies the values that are to be retained to the front of the sequence, and 2) returns an iterator that describes where the sequence of retained values ends. Ele- ments that follow this iterator are simply the original sequence values, left unchanged. Here's a simple example: Say we want to remove all even numbers from the following sequence: 123456789 Applying the remove_if algorithm results in the following sequence: 13579|XXXX The vertical bar represents the position of the iterator returned by remove_if. Note that the elements to the left of the vertical bar are the original sequence with the even numbers removed. The elements to the right of the bar are simply the untouched original members of the original sequence. If you want to actually delete items from the container, use the following technique: container.erase(remove(first,last,value),container.end()); COMPLEXITY Exactly last1 - first1 applications of the corresponding predicate are done. EXAMPLE // // remove.cpp // #include <algorithm> #include <vector> #include <iterator> #include <iostream> using namespace std; template<class Arg> struct all_true : public unary_function<Arg, bool> { bool operator()(const Arg& x){ return 1; } }; int main () { int arr[10] = {1,2,3,4,5,6,7,8,9,10}; vector<int> v(arr, arr+10); copy(v.begin(),v.end(), ostream_iterator<int,char>(cout," ")); cout << endl << endl; // remove the 7 vector<int>::iterator result = remove(v.begin(), v.end(), 7); // delete dangling elements from the vector v.erase(result, v.end()); copy(v.begin(),v.end(), ostream_iterator<int,char>(cout," ")); cout << endl << endl; // remove everything beyond the fourth element result = remove_if(v.begin()+4, v.begin()+8, all_true<int>()); // delete dangling elements v.erase(result, v.end()); copy(v.begin(),v.end(), ostream_iterator<int,char>(cout," ")); cout << endl << endl; return 0; } Program Output 1 2 3 4 5 6 7 8 9 10 1 2 3 4 5 6 8 9 10 1 2 3 4 1 2 4 WARNINGS If your compiler does not support default template parame- ters, then you always need to supply the Allocator template argument. For instance, you need to write: vector<int, allocator<int> > instead of: vector<int> If your compiler does not support namespaces, then you do not need the using declaration for std. SEE ALSO remove, remove_copy, remove_copy_if
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